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2026.08.21 16:00

106/1000, sometimes, let u equal the whole square root part

  • bprp calculus b… 오래 전 2026.08.21 16:00 인기
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    @TannuBhardwaj-…  오래 전

    Day106?

    2026-08-21 20:39

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    @Bhavya-f3u  오래 전

    ??

    2026-08-21 20:22

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    @Primalory  오래 전

    i don't understand why you don't put the +C before going back to the x world, that makes the equality wrong

    2026-08-21 19:46

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    @Bayerwaldler  오래 전

    I don’t see that it’s easier. Let u=x-1. Then x(x-1)^1/2 = (u+1)u^1/2 = u^3/2 + u^1/2, dx=du. It’s straightforward from that point on.

    2026-08-21 19:14

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    @MisterJackTheA…  오래 전

    One day he'll forget the +C, even for just a second.

    2026-08-21 18:20

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    @kamalajaiho567…  오래 전

    This question just like NCERT textbooks question i am feel that I were solve this type questions in my calss 12 time

    2026-08-21 18:15

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    @TCARK_티-시-아르크  오래 전

    Nice!

    2026-08-21 17:56

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    @vikramrawat526…  오래 전

    Day 106

    2026-08-21 17:52

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    @STARIslamicPar…  오래 전

    Nice explanation

    2026-08-21 17:22

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    @BSky2025  오래 전

    I love it ?❤️

    2026-08-22 07:49

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    @TahaHashir-o5g  오래 전

    The Council invites you

    2026-08-22 06:38

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    @matthewfeig562…  오래 전

    Pretty easy to just set u=x-1. The integral becomes Int [(u+1) sqrt u] du = Int [u^(3/2) + u^(1/2)] du.

    2026-08-22 04:28

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    @Necroplantser  오래 전

    i tried not using substitution or IBP

    x√(x-1)
    = (x-1)√(x-1) + √(x-1)
    = (x-1)^1.5 + (x-1)^0.5

    and the rest is history :D

    2026-08-22 01:44

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    @russelltaylor7…  오래 전

    x√(x-1)dx
    u=√(x-1)
    u²=x-1
    x=u²+1
    dx=2udu
    x√(x-1)dx is replaced by (u²+1)u×2udu=
    2u²(u²+1)=2u⁴+2u²=2u⁵/5 +2u³/3 + C

    (2/5)(x-1)^(5/2) + (2/3)(x-1)^(3/2) + C

    (x-1)^3/2 + (x-1)^1/2=(x-1)½[x-1+1]=x√(x-1) ✔️

    so x√(x-1)dx
     = (2/5)(x-1)^(5/2) +(2/3)(x-1)^(3/2) + C

    2026-08-22 00:44

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    @julianheller27…  오래 전

    Dieses Integral könnte man auch mit der partiellen Integration lösen. (D: x ;
    I: √(x-1)). Aber etwas unangenehm mit den neuen Exponenten 3/2 und 5/2.

    2026-08-22 00:42

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    @brainfellow514…  오래 전

    That was actually easier than it looked.  Nicely done.

    2026-08-21 22:34

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    @davidmilhousca…  오래 전

    What happens to the exponents? Why/how does it work?

    2026-08-22 11:02

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    @Mr.Chickem  오래 전

    Do I have to memorize all the series tests

    2026-08-22 10:12

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    @Tetraverse  오래 전

    Please make content on probability theory for one of these

    2026-08-22 09:36